This is a problem I saw a while back in an old issue of "CHESS" (circa 1950)
White: Kh8, Bh7, Pe2&e5;
Black: Ka2, Rh2, Bb8, Pf6&b3.
Stipulation is - White to play and force Black to mate in 5 moves, Black making the longest possible move each time.
The most obvious is something like 1e3 Rb2, 2Bc2 Bxe5 - but then..........what??
I have been trying to solve this for ages now (there was no solution I could see mentioned in subsequent issues) and it is driving me a bit nutty! Any idea, anyone?
Helpmate Problem.....
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Helpmate Problem.....
"Set up your attacks so that when the fire is out, it isn't out!" (H N Pillsbury)
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Re: Helpmate Problem.....
It looks as if the final move is going to be 5...Bxe5 mate, but it's going to be interesting making that the longest move. I mean, it's trivial to make it the bishop's longest possible move, but the rook's... You're probably going to have to force the rook to block a bishop check.
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Re: Helpmate Problem.....
1 e4 Rb2
2 exf6 Bh2
3 e5 Rg2
4 f7 Rg8+
5 fxg8 =B Bxe5#
2 exf6 Bh2
3 e5 Rg2
4 f7 Rg8+
5 fxg8 =B Bxe5#
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Re: Helpmate Problem.....
Excellent Neill! Hadn't expected a solution that quickly - seen it before?
(I had vague ideas of pushing the e5 pawn forward and under-promoting, just couldn't see how )
(I had vague ideas of pushing the e5 pawn forward and under-promoting, just couldn't see how )
"Set up your attacks so that when the fire is out, it isn't out!" (H N Pillsbury)
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Re: Helpmate Problem.....
It was new to me but I like helpmates and the mathematical part (longest move) appealed.Matt Mackenzie wrote:Excellent Neill! Hadn't expected a solution that quickly - seen it before?