Olympiad

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Lewis Martin
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Re: Olympiad

Post by Lewis Martin » Thu Aug 14, 2014 12:57 pm

A possible outcome is that Yangyi Yu, should he win today, could get 3 gold medals, and enter the 2700 club.

One team, one individual for board 3 and one for overall performance.

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JustinHorton
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Re: Olympiad

Post by JustinHorton » Thu Aug 14, 2014 1:21 pm

Topalov's drawn so Adams has to win a double rook ending for the board prize. I don't think he'll do it.
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Roger de Coverly
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Re: Olympiad

Post by Roger de Coverly » Thu Aug 14, 2014 1:33 pm

JustinHorton wrote:Topalov's drawn so Adams has to win a double rook ending for the board prize
I imagine someone has done the necessary calculations, but as Adams was facing a higher rated opponent than Topalov, he may only have needed to equal Topalov's result to overhaul him.

In the team context, Matthew Sadler drew by sacrificing two pieces for a perpetual, while Gawain looks lost. According to the chessbomb stockfish, he went wrong by playing the thematic e4 in a Nge2,e3,f3 Queens Gambit Exchange. Howell has to play ten moves on the increment, but the stockfish engine reckons he's better. He's now got the ending he seems to have been reaching all tournament, piece against pawns.

Lewis Martin
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Re: Olympiad

Post by Lewis Martin » Thu Aug 14, 2014 1:38 pm

Surely Adams still gets at least bronze? It is a draw now.

Howell could get a medal too, if he wins this game. One of the players above him was Ortiz Suarez, who drew with Sadler.

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Re: Olympiad

Post by Lewis Martin » Thu Aug 14, 2014 1:40 pm

Anish Giri has won his game. Does he go above Adams?

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JustinHorton
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Re: Olympiad

Post by JustinHorton » Thu Aug 14, 2014 2:30 pm

Ukraine are beating Hungary and should get silver. But who gets bronze?



[Edited to remove some nonsense.]
Last edited by JustinHorton on Thu Aug 14, 2014 2:54 pm, edited 2 times in total.
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JustinHorton
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Re: Olympiad

Post by JustinHorton » Thu Aug 14, 2014 2:42 pm

(I have no idea how to calculate the tie-break, by the way, and I've seen what it says on the website.)
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John McKenna
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Re: Olympiad

Post by John McKenna » Thu Aug 14, 2014 2:52 pm

Eljanov is trying to win silver for Ukraine with 48.Nc4!? (Giving the N to get passed Q-side pawns.)
Balogh refused the N so remains a pawn down but defending a blocked position.
I should think France would need to win against Russia to get a medal if Ukraine win.
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Lewis Martin
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Re: Olympiad

Post by Lewis Martin » Thu Aug 14, 2014 2:55 pm

JustinHorton wrote:Ukraine are beating Hungary and should get silver. But who gets bronze?



[Edited to remove some nonsense.]
Are they, how can Eljanov win his game?

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JustinHorton
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Re: Olympiad

Post by JustinHorton » Thu Aug 14, 2014 3:04 pm

Maybe he can't. Would that keep Hungary above other potential 17 points finishers?
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John McKenna
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Re: Olympiad

Post by John McKenna » Thu Aug 14, 2014 3:09 pm

Azerbaijan have 17 pts. in the bag but what about India-Uzbekistan?

Edit: Sasikiran has won and the others still playing.
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John McKenna
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Re: Olympiad

Post by John McKenna » Thu Aug 14, 2014 3:19 pm

Hungary 2-2 Ukraine so the Magyars also have 17 pts.
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Re: Olympiad

Post by John McKenna » Thu Aug 14, 2014 3:22 pm

Bacrot-Grischuk drawn.
Nepomniachtchi wins the match with France for Russia.
India 3.5-0.5 Uzbekistan!

Hungary, Azerbaijan, Russia & India all on 17pts.

Edit: France deleted.
Last edited by John McKenna on Thu Aug 14, 2014 3:43 pm, edited 4 times in total.
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Lewis Martin
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Re: Olympiad

Post by Lewis Martin » Thu Aug 14, 2014 3:24 pm

Russia won. I think it is currently,

China, Hungary, Russia

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JustinHorton
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Re: Olympiad

Post by JustinHorton » Thu Aug 14, 2014 3:47 pm

It's 14a here.

The position of teams that finish with the same number of match points shall be determined by application of the following tie-breaking procedures in sequence, proceeding from (a) to (b) to (c) to the extent required:

a) the sum of Sonneborn-Berger points, which are calculated as follows: match points of each opponent, excluding the opponent who scored the lowest number of match points, multiplied by the number of game points achieved against this opponent


Now I think this is confusing, and should read maybe

The position of teams that finish with the same number of match points shall be determined by application of the following tie-breaking procedures in sequence, proceeding from (a) to (b) to (c) to the extent required:

a) the sum of Sonneborn-Berger points, which are calculated as follows: match points of each opponent (excluding the opponent who scored the lowest number of match points) multiplied by the number of game points achieved against this opponent


since otherwise it looks like you're trying to multiply by the number of points scored against the excluded opponent.
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